weighted normalized fuzzy decision matrix

pone.0201604.e004">removedGRAPHIC alpha i 1 + alpha i 2 + ⋯ + alpha i j + ⋯ + alpha i p=1
otherwise<disp formula id="pone.0201604.e046">removedGRAPHIC Max Z=∑ i=1 n ∑ j=1
i j</disp formula><disp formula id="pone.0201604.e047">removedGRAPHIC s. t. ∑ i=1 n ∑ j=1
B T</disp formula><disp formula id="pone.0201604.e048">removedGRAPHIC ∑ j=1
j (1 - d i j)<D i, i=1..., m</disp formula><disp formula id="pone.0201604.e049
i=1..., m, j=1..., n</disp formula><disp formula id="pone.0201604.e050
i=1..., m, j=1..., n</disp formula><disp formula id="pone.0201604.e051
pone.0201604.e079">removedGRAPHIC z=184.200 ;</disp formula><disp formula id="pone.0201604.e080">removedGRAPHIC x 11=100 ; x 12=50 ; x 13=200 ; x 14=0 ;</disp formula><disp formula id="pone.0201604.e081">removedGRAPHIC y 11=1 ; y 12=1 ; y 13=1 ; y 14=0

Striatal transcriptome of a mouse model of ADHD reveals a pattern of synaptic remodeling

density of synaptophysin particle estimation

n=10 per bar. A D. Amotl2, Dpysl5, Ctnnbip1

Continuous nicotine exposure does not affect resurgence of alcohol seeking in rats

alternative reinforcement follow up model

chi^2(2)=30.61, p<.0001). removedGRAPHIC Fig 2

A dynamic bid price approach for the seat inventory control problem in railway networks with consideration of passenger transfer

t + 1 x t - v t + 1 x t - A k ] + v t + 1 x t } ∀ t, x t ∈ X</disp formula><disp formula id="pone.0201718.e009">removedGRAPHIC v t(0)=0 ∀ t=1..., T</disp formula><disp formula id="pone.0201718.e010">removedGRAPHIC v T + 1 x T + 1)=0 ∀ x T + 1
pone.0201718.e030">removedGRAPHIC F S={ i | ∑ j ∈ S 1 { i ∈ j }<1, ∀ i ∈ I }</disp formula>-1
d + 1 phi (d + 1) - phi d + ∑ i ∈ F S π alpha + 1, i Q ¯ d, i S<R ¯ d S ∀ d=1
t + 1, i ∀ t=alpha..., T, i θ ¯ d<θ ¯ t + 1 ∀ d=1..., D alpha θ t<θ t + 1
T</disp formula><disp formula id="pone.0201718.e046">removedGRAPHIC π ~ t, i={ π alpha + 1, i t=1..., alpha -1
Algorithm 1 Dynamic Disaggregated DD Approach<p specific use="line">1
alpha + 1, i Q ¯ d, i S - θ ¯ d - θ ¯ d + 1 phi (d + 1) - phi d ∀ d=1
then S ≔ S ∪ { j }.<p specific use="line">3